A lady runs 18km towards East and then24km towards North how far is she from her starting point and in which direction?

a.42km North-east
b.42km east
c.6km east
d.30km north-east

• using formula
  h^2=b^2+l^2
  h^2=24^2+18^2
  h^2=900
  h=30
  option d is right
• 9 years agoHelpfull: Yes(19) No(0)
• ans-d)towards east= 18 km
  towards north=24 km
  direction =north east
  applying Pythagorean triplet=(3,4,5) = 3*6=18, 4*6=24, 5*6=30)
  so distance=30 km
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• Ans-(d) 30km north east
  
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• Ans Is:30km North East
• 9 years agoHelpfull: Yes(1) No(0)
• 30km north-east
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• option d by hypotenuse theorem
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• Ans - d 30 km
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• 30km NorthEast since by formula AC^2=AB^2+BC^2;
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• (18)^2+(24)^2=30km north-east
  
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• by pythgorus triples
  a^2+b^2=c^2
  18^2+24^2=900
  so ans is 30 km
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• 30km northeast
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• ans is a:42km north-east
  lady runs in right angle path..apply a*a+b*b=h*h
• 9 years agoHelpfull: Yes(0) No(1)
• h^2=b^2+l^2
  h^2=24^2+18^2
  h^2=900
  h=30
  ans is 30 km north east
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• 24^2+18^2=a^2
  576+
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• ans : b)
  42km east
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• option D is right
  
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• 30
  SQRT(24^2+18^2)
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• 42 km east
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• H^2=L^2+B^2
  Here L=24 and B=18
  so H^2=24^2+18^2
  =900
  under root 90 is 30
  So the answer would be 30.
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• applying pythagorous theorm
  let distance from starting point be X
  x^2=18^2+24^2
  x=30
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• When you observe it carefully we can see the formation of triangle.
  so by cuing the formula xpower 2=sqrt(24 square +18 square)
  therefore x=30Km north-east
• 8 years agoHelpfull: Yes(0) No(0)
• 30 km towards north east
• 8 years agoHelpfull: Yes(0) No(0)
• 18km east then from there she will run 24 kms north(i.e from tip of 18 kms a refference she will move in north it is same as east )
  so total is 42 km east
  
• 8 years agoHelpfull: Yes(0) No(1)
• sqrt(24^2+18^2)=30km north-east
• 7 years agoHelpfull: Yes(0) No(0)