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what is the chance that a leap year selected at random contains 53 fridays?
Read Solution (Total 7)
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- in leap year 52 weeks and 2days
either (thursday,friday) or (friday, saturday)
probability(2 fridays)=2/7
- 10 years agoHelpfull: Yes(3) No(0)
- ans is: 2/7
- 10 years agoHelpfull: Yes(2) No(0)
- ans:2/7.bcz in leap year 52 weeks and 2 days.
- 10 years agoHelpfull: Yes(1) No(1)
- answer is 2/7
- 10 years agoHelpfull: Yes(1) No(0)
- n leap year 52 weeks and 2days
either (thursday,friday) or (friday, saturday)
probability(2 fridays)=2/7
- 10 years agoHelpfull: Yes(0) No(1)
- ans : 2/7
- 10 years agoHelpfull: Yes(0) No(0)
- 147.505
1+3+5+7+....199=199^2
-2-4-6-.....-200= -2(1+2+3+4+....`100)
=-100*101
now adding above values
(199^2-100*101)/200=147.505
- 10 years agoHelpfull: Yes(0) No(4)
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