A cow Horse brought for Rs 2000 The cow is sold at a profit of 20 and the Horse is

c+H=2000---1
(20c-10H)100=40
20C-10H =4000----2
substitute value grom eq 1 in 2...
c=800
12 years agoHelpfull: Yes(8) No(0)
COST PRIZE OF COW =800
let cost prize of cow x and horse 's 2000-x.
then from question selling prize of cow = 120x100.
and selling prize of horse is =90(2000-x)100.
then 120x100+90(2000-x)1000=2040
120x+90*2000-90x=2040*1000
after solving equation we get x=800.
12 years agoHelpfull: Yes(7) No(6)
ans x=800
let cost price of cow is x and cost price of horse is y;
x+y=2000;
20x-10y=4000;
by solving this two equations ;
x=800.
12 years agoHelpfull: Yes(4) No(1)
let cow = Rs.x and horse = Rs.y
then x+y = 2000 ------(1)
120%x+90%y=2040(Rs.40gain)
=>12x+9y=20400 ---(2)
From Equation (1) 12x+12y=24000 ----(3)
Eq'n (3)-(1) =>3y=3600=>y=1200(horse price)
But cow price= 2000-1200=Rs.800
12 years agoHelpfull: Yes(3) No(1)
ans is 800
C+H=2000
(20C/100)+(10H/100)=40
=>H=2C-400
C+2C-400=2000
=>C=800
12 years agoHelpfull: Yes(1) No(1)
let cost price of cow is x than horse is 2000-x
salling price of cow = x*(120/100)= 6x/5 bz 20% profit
salling price of horse=(2000-x)*(90/100) = (2000-x)*9/10 bz 10%loss
Total salling price
sp of cow+sp of horse= cp of cow +cp of horse+gain
6x/5 + (2000-x)*9/10 =2040
by solving this u will get x=800
12 years agoHelpfull: Yes(1) No(1)

A cow & Horse brought for Rs.2000. The cow is sold at a profit of 20% and the Horse is sold at a loss of 10%. Of The overall gain is Rs.40. The cost price of the cow is :
a) 700 b) 800 c) 1200 d) 1300