roy is now 4 years older than erik and half of that amount older than iris. if in 2 years, roy wil be twiceas old as erik then in two years what would be roy's age multiplied by iris age
a)28
b)48
c)50
d)52

• At present
  roy=erik+4....(1)
  roy=iris+2....(2)
  In 2yrs,
  roy+2=2(erik+2)
  (erik+4)+2=2(erik+2)....from(1)
  erik=2yrs
  so,roy=6yrs
  iris=4yrs
  after 2years
  roy*iris=8*6=48
• 12 years agoHelpfull: Yes(130) No(9)
• At present
  age of roy ... 6 yrs, age of erik = 2 yrs, age of iris = 4 yrs
  after 2 yrs , age of roy = 8 yrs, age of iris = 6 yrs
  After two years roy's age multiplied by iris age = 8*6= 48 yrs
  
• 12 years agoHelpfull: Yes(20) No(8)
• given that now roy is 4 years older that eric so
  roy=4+eric -->1
  and half of that older than iris
  roy=2+iris -->2
  in 2years roy is twice as old as erick
  roy+2=2(eric+2)
  roy=2eric+2
  substitute in eq 1
  2eric+2=4+eric
  eric=2
  roy=4+2=6
  iris=roy-2= 6-2= 4
  these are prresent ages of roy=6 eric=2 and iris=4
  after 2 yeas roy=8 and iris=6
  6*8=48
  
  ans:b
• 10 years agoHelpfull: Yes(6) No(2)
• exlaim properly
• 12 years agoHelpfull: Yes(5) No(4)
• 
  Roy is now 4 years older than Erik --> R=E+4
  Roy is now ... half of that amount older than Iris --> R=I+frac{4}{2}=I+2 (half of the amount of 4)
  In 2 years, Roy will be twice as old as Erik --> R+2=2(E+2) (in 2 years for both Roy and Eric)
  
  Then in 2 years what would be Roy’s age multiplied by Iris’s age --> (R+2)(I+2)=?
  
  Solving: R=6 and I=4 --> (R+2)(I+2)=48
  
  Answer: C.
• 9 years agoHelpfull: Yes(3) No(0)
• Let present age of Roy be x.
  Eric is 4 yrs younger than Roy->x-4
  Iris is 2 yrs younger than Roy->x-2
  In 2 yrs( According to the problem)
  x=2(x-4) ->x=8(Roy's age)
  Iris age=6,Eric's age=4
  Hence Iris age*Roy's age=6*8=48
  
  
  
• 8 years agoHelpfull: Yes(3) No(0)