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Maths Puzzle
Numerical Ability
Ratio and Proportion
A and B are two alloys of gold and copper prepared by mixing metals on the ratios 5:3 and 5:11 respectively. Equal quantities of these alloys are melted to form a third alloy C. The ratio of gold and copper in the alloy C is :
Read Solution (Total 5)
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- A contains Gold=5/8 Copper=3/8
B contains Gold=5/16 Copper=11/16
After mixing A & B , C will have Gold=5/8+5/16=15/16 & Copper=3/8+11/16=17/16
Therefore ratio of Gold:Copper=15/16 : 17/16 =15:17 - 12 years agoHelpfull: Yes(10) No(2)
suppose 16 units of each alloy is mixed , then
32 units of final alloy will have A and B in ratio of
(10+5) : (6+11) or 15:17- 12 years agoHelpfull: Yes(8) No(3)
- explain it clearly.
- 12 years agoHelpfull: Yes(0) No(3)
- Alloy A : 8x(Gold=5x/8 and copper=3x/8)
Alloy B : 16y(Gold= 5y/16 and copper= 11y/16)
now it is written there it should be in equal proportion so
(5x/8)+(5y/16)=(3x/8)+(11y/16)
i.e. x/y= 3:2 - 7 years agoHelpfull: Yes(0) No(0)
- 7/5 no explanation
- 7 years agoHelpfull: Yes(0) No(0)
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