there are 4 boxes colored red, yellow ,green and blue. if 2 boxes are selected,how many combinations are there for at least one green box or one red box to be selected?
a)1
b)6
c)9
d)5

• ans is 5
  combinations of the 4 boxes like
  red, yellow
  red,green
  red,blue
  yellow,green
  green,blue
• 11 years agoHelpfull: Yes(118) No(12)
• Ans. (d) 5
  
  1. Red, Green
  2. Red, Blue
  3. Yellow, Green
  4. Yellow, Red
  5. Green, Blue
• 11 years agoHelpfull: Yes(24) No(3)
• answer is 5 not 6 (in tcs it showed 6 as wrong ans)
• 11 years agoHelpfull: Yes(23) No(6)
• _ _(two boxes to be filled),now box1 may be R or G so,2c1 and remaining colors are 3 and remaining box is one so 3C1 finally 3C1*2C1=6
• 11 years agoHelpfull: Yes(13) No(30)
• ans is 6
  there are 4 boxes.to select 2 boxes it is 4c2
  to select red box or green box the possibility is only 1
  so total combinations will be 4c2*1*1=6.
• 11 years agoHelpfull: Yes(9) No(43)
• 1c1*3c1+1c1*3c1-1=5
  
  +sign as green or red and -1 because been and red and red and green is same combination
  
  also,
  
  1c1*2c1+1c1*2c1+2c2=2+2+1=5
  statement
  1c1 for red and 2c1 for non required color
  same for green
  and 2c2 for the event that both boxes can be the required colored
• 10 years agoHelpfull: Yes(8) No(3)
• [(1c1*2c1)*2]+1=5
• 11 years agoHelpfull: Yes(4) No(14)
• here green and green be a combination because given condition for green balls is at least 1 means 2 green balls could be possible.
  therefore, green green
  red green
  red blue
  red yellow
  green blue
  green yellow
• 11 years agoHelpfull: Yes(3) No(2)
• to choose 1 fem 2colored and 1 frm 3colored boxes
  
  2c1+3c1=5
  ans) 5
• 10 years agoHelpfull: Yes(2) No(3)
• 5
  2c1*2c1+2c2=5
• 9 years agoHelpfull: Yes(2) No(0)
• the two boxes can be selected as
  R Y
  R G
  R B
  Y G
  Y B
  G B
  combination including atleast one red or green is 5
  so ans is d)5
• 9 years agoHelpfull: Yes(1) No(1)
• here they given that atleast one red box or one green box.....so the combinations are 7
  RR
  RG
  RB
  RY
  GB
  GY
  GG
• 8 years agoHelpfull: Yes(1) No(4)
• 5 is right answer..
  1c1 * 2c1 + 1c1 * 2c1 + 2c2 = 5
• 9 years agoHelpfull: Yes(0) No(4)
• we can select two out of 4 boxes in the following ways:
  red,yellow
  red,green
  red,blue
  yellow,green
  yellow,blue
  green,blue.
  total 6 combinations possible.
  out of these to be one green or red box to be selected is 5(as it includes the case of yellow,blue)
• 8 years agoHelpfull: Yes(0) No(0)
• ans is 5 bcz 2 combination are select r,g
  so r,y
  r,b
  r,g
  g,y
  g,b
  
• 8 years agoHelpfull: Yes(0) No(0)
• (3 combination of green + 3 combination of blue)-((green and blue) or (blue or green))=5
• 8 years agoHelpfull: Yes(0) No(1)
• Total ways of selecting two boxes out of 4 is 4C24C2 = 6. Now, the number of ways of selecting two boxes where none of the green or red box included is only 1 way. (we select yellow and blue in only one way). If we substract this number from total ways we get 5 ways
• 8 years agoHelpfull: Yes(0) No(0)
• Red , green combination should be counted because they mentioned at least one color not at most one color
  
  So answer is 6
• 7 years agoHelpfull: Yes(0) No(1)
• ans is 5
  combination possible........
  red, yellow
  red,green
  red,blue
  yellow,green
  green,blue
  
• 7 years agoHelpfull: Yes(0) No(0)
• If one is either green or red then only one box is left empty it can be of any colour ..remaining are 3 therefore 3!= 6 ways
• 6 years agoHelpfull: Yes(0) No(0)
• Total ways of selecting two boxes out of 4 is
  4
  C
  2
  = 6. Now, the number of ways of selecting two boxes where none of the green or red box included is only 1 way. (we select yellow and blue in only one way). If we substract this number from total ways we get 5 ways.
• 5 years agoHelpfull: Yes(0) No(0)