If x^2-16>0, which of the following must be true?
a)-4>x>4
b)-4>x

• X^2 - 16 > 0
  So We have to take X above 4 and below -4...
  Ans is -4>x and 4
• 11 years agoHelpfull: Yes(17) No(1)
• a^2-b^2=(a+b)(a-b)
  (x^2-4^2)=(x-4)(x+4)
  so x=-4,4
  so value of x can be 4 and -4,so value lying between these two,so a)-4>x>4 is true(ans)
• 11 years agoHelpfull: Yes(16) No(27)
• X^2-16>0
  X^2>16.
  X SHOULD BE ABOVE 4
  QUESTION IS WRONG
• 11 years agoHelpfull: Yes(6) No(1)
• x^2-16>0
  => (x+4)(x-4) >0
  2 cases arises
  1.either 2 nos will be +,den der multiplication will b >0
  2.or 2 nos will be -ve,den also der multiplication will b >0
  so,
  either(x+4)>0 and (x-4)>0
  or;(x+4)x
• 11 years agoHelpfull: Yes(2) No(1)
• x^2-16>0
  so x must be less than -4 and x has to be greater than +4 to satisfy the given equation..
• 11 years agoHelpfull: Yes(2) No(1)
• sry d ans z nt gng..
  from d abv we can know x will lie in between
  -4>x
• 11 years agoHelpfull: Yes(1) No(2)
• x^2-16>0
  x^2>16
  x>sqrt(16)
  x>=4 or -4
  so,
  x>4 or x
• 7 years agoHelpfull: Yes(1) No(0)
• [sanjana]
  x^2-16>0
  => (x+4)(x-4) >0
  2 cases arises
  1.either 2 nos will be +,den der multiplication will b >0
  2.or 2 nos will be -ve,den also der multiplication will b >0
  so,
  either(x+4)>0 and (x-4)>0
  or;(x+4)
• 11 years agoHelpfull: Yes(0) No(4)
• it should be -4>x>4..
  lets us take x=+5 or -5
  then x^2-16=25-16=9>0(condition satisfied)
  now +5>4 and -54 and xx>4.
  9a0 is correct.
  
• 11 years agoHelpfull: Yes(0) No(2)
• if there is and option like -4>x>4
• 10 years agoHelpfull: Yes(0) No(1)
• i think ans is -4>x
• 10 years agoHelpfull: Yes(0) No(1)
• this question is wrong. x should be more than 4 to be greater than 0. i.e, suppose x is more than -4 and less than 4. suppose it is 3 then x^2 =9 which is less than 4^2 in this case the ans will not satisfy x^2-6>0 ans suppose x is more than 4. x is 5 then this relation will satisfy as
  X^2-16>0 when x is=5
  
• 8 years agoHelpfull: Yes(0) No(0)
• -4>x>4..as x should be less than -4..ie.-5,-6,-7...and x should be greater then 4 ie 5,6,7....
• 8 years agoHelpfull: Yes(0) No(0)
• x> + - 4
  then if x >4
  it is obvious dat x> -4
  mi r8??
  
• 8 years agoHelpfull: Yes(0) No(0)
• a^2-b^2=(a+b)(a-b)
  (x^2-4^2)=(x-4)(x+4)
  so x=-4,4
  1) is true
  
• 7 years agoHelpfull: Yes(0) No(0)
• x^2-16>0
  (x-4)(x+4)>0
  hence, x4
• 6 years agoHelpfull: Yes(0) No(0)