In base 7, a number is written only using the digits 0,1,2...6. The number 135 in base 7 is 1*7^2+3*7+5=75 in base 10. what is the sum of the base 7 number 1234 and 6543 in base 7?
a)11101
b)11110
c)10111
d)11011

• Ans:b
  
  Here it is Asked to find the sum of base 7 number 1234 and 6543.
  Add the two number.
  1234+6543=7777
  Now as per base 7 rule:
  Divide 7777 by 7,you will get 1111 as quotient and remainder as 0.
  Hence 11110.
• 12 years agoHelpfull: Yes(50) No(6)
• 7 in base 7 = 10
  so 1234
  +6543
  -------
  4+3 = 0
  1 carry
  4+3+1 = 8 = 11
  1 carry
  2+5 + 1 =11
  1 carry
  6+1+1 = 8 = 11
  so 11110
• 12 years agoHelpfull: Yes(18) No(4)
• 343+98+21+4=466 (1234)
  2058+245+28+3=2334 (6543)
  thus addition in decimal=2800
  now convert 2800 to base 7= 11110
  7!2800 ! 0
  --------
  7!400 ! 1
  --------
  7! 57 ! 1
  --------
  7! 8 ! 1
  --------
  1 ! 1
  2800 (in decimal)==11110 (in base 7)
  
• 9 years agoHelpfull: Yes(4) No(3)
• b)11110
  
  .1234 ..... in base 7
  +6543........In base 7
  
  ---------
  11110........In base 7
  -------
• 12 years agoHelpfull: Yes(1) No(23)
• (1234) = 7^3x1+7^2 x2 +7x3+ 4 = (466)10
  (6534) = 7^3x6 + 7^2x5 + 7x6 + 7 = (2328)10
  2328+466 = 2794
  for 2794 = 7^4 + 7^3 +7^2 +7*0 + 7 = (11101)base7
• 7 years agoHelpfull: Yes(0) No(0)