If p(x)=a(x^4)+b(x^3)+c(x^2)+dx+e has roots at x=1,2,3 and 4, and P(0)=48, what is P(5)?
a)48
b)24
c)0
d)50

• 48
  
  if 1 is a root then x-1 is a factor of p(x)
  similarly x-2 is a factor,x-3 ,x-4 are factors
  
  but p(x) is 4th degree polynomial therefore it can be in the form
  
  p(x) = k(x-1)(x-2)(x-3)(x-4) , where k is a constant
  
  but given p(0) =48
  
  therefore 24 k =48
  
  k=2
  
  p(x) =2(x-1)(x-2)(x-3)(x-4)
  
  p(5)= 2*4*3*2*1 = 48
• 11 years agoHelpfull: Yes(24) No(6)
• this question already solved by me as q.no = #M40010640. you are just copying it without changing a small word .
• 11 years agoHelpfull: Yes(6) No(4)