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what should be the highest value that must be assigned to #. So that the number 10114#5 is exatly divisible by 7?
a.5
b.6
c.7
d.8
e.9
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- ans b 6
by trail and error method - 9 years agoHelpfull: Yes(2) No(0)
- ans is 6...
- 9 years agoHelpfull: Yes(1) No(0)
- 7-- highest value
- 9 years agoHelpfull: Yes(0) No(3)
- b. 6
By hit and trial - 8 years agoHelpfull: Yes(0) No(0)
- b-6 , after division wew will get 6 before # so there should be some number which after dividing by 7 leaves a number so that 35 comes at the end.this is possible only when #=3.so 7*9=63 and 3 will come and remainder which again becomes 35 when 5 gets down.
- 7 years agoHelpfull: Yes(0) No(0)
- b. 6
By hit and trial - 6 years agoHelpfull: Yes(0) No(0)
- ans is 6 bcoz when you divide 66 from 63 then only 35 will be divisible from 7.,
- 4 years agoHelpfull: Yes(0) No(0)
- option b is correct
- 1 year agoHelpfull: Yes(0) No(0)
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