Jhon works for 60 days. for the day he is present he is paid 7.00/- and for the day he is
absent he is paid 3.00/- per day. if he is paid 170/-.how many days he is present.

• let no. days be = x and no. days he is absent = 60-x , so 7x - 3(60-x) = 170
  x = 35
• 12 years agoHelpfull: Yes(19) No(10)
• The given statement/question seems to be wrong.
  
  let no. days be = x and
  hence no. days he is absent = 60-x ,
  so as per given statement
  7x + 3(60-x) = 170
  4x+180= 170
  4x= -10
  x= -5/2
  
  which is not possible.
  
  
• 12 years agoHelpfull: Yes(16) No(8)
• the question is a little bit wrong... it shud be..jhon have to pay 3 rupees when he is absent
• 10 years agoHelpfull: Yes(13) No(1)
• ans is 35 days present... and que has a mistake that if he is absent 1 day den he gave 3 rs as penalty...
  thats y 35 days present cost rs 35*7=245 and 25 days absent cost 75 penalty... so
  245-75=170.......
• 10 years agoHelpfull: Yes(4) No(1)
• 7x-3y=170, x+y=60. on solving, we get x=35, y=25.
• 8 years agoHelpfull: Yes(2) No(0)
• 7x-3y=170
  by hit aand trial
  7x should be 210
  and 3y should be 40.
  so no. of working days is 30.
• 10 years agoHelpfull: Yes(0) No(2)
• 3*60=180 so its impossible.
• 8 years agoHelpfull: Yes(0) No(0)