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A hallow cube of 5cm is taken, with thickness of 1 cm.It is made of smaller cudes of 1 cm.If 5 faces of outer cude are painted,then totally how many smaller cubes surfaces reamin unpainted?
a)475 b)900 c)775 d)463
Read Solution (Total 13)
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- TOTAL NO OF SMALLER CUBES=5*5*5-3*3*3=98 cubes
so total faces = 98*6=588
total no of painted cubes=5*25=125
so unpainted cubes=588-125=463 - 14 years agoHelpfull: Yes(13) No(1)
- 463
- 14 years agoHelpfull: Yes(1) No(1)
- 463
- 14 years agoHelpfull: Yes(1) No(1)
- 588-25(no of unpainted surfaces)=588-25*5=588-125=463
Ans d - 14 years agoHelpfull: Yes(1) No(1)
- outer cube has 6 faces.
each face has 25 small cubes bcoz each small cube is of 1 cm.
5 faces of outer cube is painted and one is not so 6th face has 25 smaall cube with 6 faces of each so there are 25*6=150 faces unpainted.
and remaining 5 faces of outer cube has total 125 small cubes(as one face has 25 smaal small cube so,25*5=125),here only outer face of the each of 125 cubes is painted so remaining 5 faces of each 125 smaal cube is not painted so there are 125*5=625 faces are unpainted.
finally,150+625=775 faces of smaaler cubes remain unpainted.
ans-c)775 - 14 years agoHelpfull: Yes(1) No(9)
- ans is 475
- 11 years agoHelpfull: Yes(1) No(0)
- ans d) 463
- 14 years agoHelpfull: Yes(0) No(2)
- d)463
- 14 years agoHelpfull: Yes(0) No(1)
- 5^3-3^3=98
total face= 98*6=588
5 faces of large are painted means 25*5=125
then unpainted face is 588-125=463 - 14 years agoHelpfull: Yes(0) No(1)
- total no. of faces painted=5*(5*5)=125
no. of cubes required to make the hollow cube= 25+25+18+15+15=98
total no. of faces= 98*6=588
so no. of unpainted faces(surfaces)=588-125=463
ans (d) 463 - 14 years agoHelpfull: Yes(0) No(1)
- 463
- 14 years agoHelpfull: Yes(0) No(1)
- (5*5*5)-(3*3*3)=98
98*6=588;
588-(5*25)=463
- 14 years agoHelpfull: Yes(0) No(1)
- 588-25*n
where n is the no of unpainted cube sides
588-25(no of unpainted surfaces
588-25*5
588-125
=463
Ans d - 14 years agoHelpfull: Yes(0) No(1)
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