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X and Y are independent random variables with variance 2 and 3. Find the variance of 3X+4Y
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- var(3X+4Y)=3^2 var(X)+4^2 var(Y)=9*2+16*3=18+48=66
answer is 66
- 8 years agoHelpfull: Yes(0) No(0)
- Var (3X+4Y) = (3)^2 Var (X) + (4)^2 Var(Y)
= 9.2 + 16.3
= 8 + 48
Var (3X+4Y) = 56. - 1 year agoHelpfull: Yes(0) No(0)
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