A metal strip of width 'X'cm. 2 metal strips are placed one over the other, then the combine length of 2 strips is 'Y'. if 'Z' strips are placed in that manner.what is the final width of that management?

• metal strip width is x
  it can not be changes if any number of plate placed over it
  hence ans is X
• 13 years agoHelpfull: Yes(17) No(11)
• First see diagram of Q9 in link:
  https://writer.zoho.com/public/suchandra/ques
  Total z strips are there with x width. So total width will be Z*X. Length Y is only to confuse you.
• 12 years agoHelpfull: Yes(9) No(3)
• width of 1st strip = X & now z-1 strips are left
  and hence total width = X+(z-1)*(y-x)
• 13 years agoHelpfull: Yes(7) No(9)
• Total width= xz
  Y is irrelevent.
• 13 years agoHelpfull: Yes(5) No(7)
• width of two metal strips = 2X = Y;
  therefore width of Z strips = ZX,,,,
• 13 years agoHelpfull: Yes(3) No(8)
• width of 1 strip=X cm
  hence width of such Z strips =Z*X
• 13 years agoHelpfull: Yes(2) No(6)
• x only
• 13 years agoHelpfull: Yes(2) No(6)
• x
• 13 years agoHelpfull: Yes(2) No(6)
• Width will be X
• 13 years agoHelpfull: Yes(2) No(6)
• length of first metal strip=x
  length of 2nd metal strip=y-x
  so,length of z metal strips of type 2nd=z*(y-x)
  total final width=x+z*(y-x)
• 13 years agoHelpfull: Yes(2) No(7)
• width of 1st strip = X & now z-1 strips are left
  and hence total width = X+(z-1)*(y-x)
  proceed by taking as 1,2,3,4 and think corresponding....
• 13 years agoHelpfull: Yes(2) No(4)
• we are talking only about width and not length, so neglect the length y!
  
  final width = xcm
• 13 years agoHelpfull: Yes(2) No(3)
• ans is x + (y-x)(z-1)
  its an A.P...i.e a+[(n-1) * d] ==> a = first term, n = total no., d = cmmn diff.
  say eg: say metal strip width 2 cm, 2 strips combining say 3 and total 5 strips so total sum of width wud be 2+(5-1)(3-2) = 8.
• 13 years agoHelpfull: Yes(2) No(5)
• 2Z will b the final width of the strip
• 13 years agoHelpfull: Yes(0) No(14)
• I am still confusing,so explain the question correctly
• 4 years agoHelpfull: Yes(0) No(0)