A father with 8 children takes 3 at a time to the zological garden, as often as he can,without taking the same 3 children more than once.how often he will go and how ofen will each child go? a)56,35 b)92,42 c)56,21 d)56,42

• ANSWER- 21
  
  solution:
  possible no of groups (each containing 3 children) = 8C3= 56
  father goes with every group hence he will go 56 times.
  total children in 56 trips =56*3
  as there are 8 different children, no of trips of each child=(56*3)/8=21
• 11 years agoHelpfull: Yes(40) No(1)
• ans :- c)56,21
  
  no of possible groups= 8c3=56
  hence father will go 56 times
  total children in 56 groups= 56*3
  there are 8 children hence no of trips for each child=(56*3)/8=21
• 11 years agoHelpfull: Yes(6) No(0)
• c)56,21
  
  A father with 8 children takes 3 at a time to the zological garden, as often as he can,without taking the same 3 children more than once.
  
  Number of possible groups = 8C3 = 8*7*6/6 = 56
  
  Each child will have equal chance to go to Zoo.
  So number of time , each child can go to zoo = 56*3/8 = 21
  
• 11 years agoHelpfull: Yes(2) No(0)
• no of visits=8C3=8!/(3!5!)=56
  visit of each child=7C2=7!/(2!5!)=21
• 11 years agoHelpfull: Yes(2) No(2)