Q A bag contains 4 white 5 red and 6 blue balls Three balls are drawn at random from the

its 2/91
solution: (5/15)*(4/14)*(3/13)=2/91
12 years agoHelpfull: Yes(10) No(3)
5c3/15c3=10/455=2/91(ANS)
12 years agoHelpfull: Yes(9) No(1)
15c3=455
5c3=10
so, 10/455=2/91
12 years agoHelpfull: Yes(7) No(0)
ans:2/91
number of ways of selecting three balls from 5 red balls = 5c3 = 10
total number of ways to select three balls randomly from (6+5+4)=15 balls= 15c3
=455
probability of getting three balls from red= 5c3/15c3 = 10/455 = 2/91
12 years agoHelpfull: Yes(3) No(0)
Total events of selecting 3 balls =15c3=455
Events of selecting 3 red balls=5c3=10

Probability of selecting only red balls =10/455
=2/91
12 years agoHelpfull: Yes(3) No(0)
5c3/15c3=10/455=2/91(ans)
12 years agoHelpfull: Yes(1) No(0)
itsP(red ball)= 5c3/15c3=2/91
12 years agoHelpfull: Yes(1) No(0)

Q. A bag contains 4 white,5 red and 6 blue balls.Three balls are drawn at random from the bag.the probability that all of them are red are????