in a reading room of library , there are 10 tables and each table has 4 chairs.at each table , there are different no of people seated . how many tables are left out without atleast one person?

• since there are different no of people seated at every table , so at most 4 tables can be filled with the person count on each table being 1,2,3,4 respectively..
  so, 6 tables would be left out without at least 1 person..
• 12 years agoHelpfull: Yes(5) No(0)
• im not clear with the question so could you pls elaborate it correctly
• 12 years agoHelpfull: Yes(2) No(1)
• 6
  1+2+3+4 seated different no. of peoples
  four tables are in use remain 6 are free
• 12 years agoHelpfull: Yes(1) No(0)
• answer is 6
  
  there are 4 chairs on each table so maximum possible people on one table are 4
  
  and on each different number of people are there.!
  
  so 1 on 1 table
  then 2 on 2nd one
  then 3 on 3rd one
  then 4 on 4th one
  so left tables are 10 - 4 = 6
• 12 years agoHelpfull: Yes(1) No(0)
• @M.Sridevi : its saying that u have to place "DIFFERENT" number(count) of people at each and every table..
  thats why i gave the answer as such.
• 12 years agoHelpfull: Yes(0) No(0)
• he did not give max num of people who are seated ryt.assuming 40 chairs we can consider 40 to b max num of people...sry im nt clear
• 12 years agoHelpfull: Yes(0) No(0)
• there are 10 tables and each table has 4 chairs .
  at each table there are different no of people seated
  first table=4
  second table=3
  third table=2
  fourth table=1
  
  not any seated other different
  so blanked table
  10-4=6
• 12 years agoHelpfull: Yes(0) No(0)