There is 7 friends (A1, A2, A3....A7). If A1 have to have shake with all with out repeat. How many hand shakes possible?(

• 6 because according to the q only a1 handshake with others
  so total handshakes are 6
  (a1-a2,a1-a3,a1-a4,a1-a5,a1-a6)
• 11 years agoHelpfull: Yes(14) No(0)
• ans:6 because it will not shake his hand with itself
• 11 years agoHelpfull: Yes(12) No(2)
• 6+5+4+3+2+1=21(ans)
• 11 years agoHelpfull: Yes(8) No(20)
• but he was talking about handshake of a1 with others
• 11 years agoHelpfull: Yes(3) No(1)
• Guys dont always b on the formulas.....sometimes even commonsense works...dis ques is abt A1 only....so its 6....
• 11 years agoHelpfull: Yes(3) No(0)
• 6 handshake are possible.!!
  
  according to question A1 have to shake hand with others so (A1,A2)(A1,A3)(A1,A4)(A1,A5)(A1,A6)(A1,A7)
• 11 years agoHelpfull: Yes(2) No(0)
• solution is 6..
  bcz people who write 21 dont see that we have to count distinct shake hands by only a1.. nt by all ...
  so a1 will shake hands with remianing 6 w/o his self ...
• 11 years agoHelpfull: Yes(2) No(0)
• keeping a1 aside there are 6 members.for a1 to shake hands with other 6 without repetition there are 6 possibilities
• 11 years agoHelpfull: Yes(1) No(2)
• if in questn said about cyclic handshake then 7c2.
  and if without cylic handshake then 7-1=6.
• 11 years agoHelpfull: Yes(1) No(4)
• only 6 (ans)
• 11 years agoHelpfull: Yes(1) No(0)
• Ans:720
  According to condition:without repeatation
  7 persons have 6 shakehands
  remaining 6 persons have 5 shakehands
  remaining 5 persons have 4 shakehands
  remaining 4 persons have 3 shakehands
  remaining 3 persons have 2 shakehands
  remaining 2 persons have 1 shakehands
  so 6*5*4*3*2*1=720
• 11 years agoHelpfull: Yes(0) No(30)
• The number of persons(n)= 7
  Without Repeat so we can use =(n-1)
  Answer=(7-1)
  =6
• 11 years agoHelpfull: Yes(0) No(0)