Roy is now 4 year older than Erik and half of that amount than Lewis.If in two years Roy will be twice as old as Erick,then in two year what would be Roy age multiplied by Lewis age??

• ans is 48
  firstly two equation from 1st sentence ..
  suppose roy=x, erik=y, lewis=z
  so x=y+4....(1)
  2nd is x=z+2...(2) (Roy is now 4 year older than Erik and half of that amount than Lewis so 4/2=2)
  also after 2 years erik and roy relation wil b
  x+2=2(y+2).. (3)
  so put this into 1st equ. u will get y=2..
  and then x=6,z=4(by substituting other)
  nw asking multiplication after two years of roy n lewis is (6+2)*(4+2)=48..
  
• 12 years agoHelpfull: Yes(75) No(8)
• Ans 112
  Let age of Roy,Erik & Lewis be R,E & L respectively
  According to condition R=4+E=L/2 --(i) and R+2=2(E+2)=>R=2E+2 --(ii)
  Comparing (i) & (ii) for R, we get E=2, So R=6 and L=12
  In two years R=8 and L=14, therefore R*L=8*14=112
• 12 years agoHelpfull: Yes(17) No(17)
• let roy,erik,lewis age are A,B& C
  by 1st sentence A=B+4
  by 2nd sentence (A+2)=2(B+2) and C=2A by solvind it we get A=6 B=2 & c=12
  and after two years A*C=8*14=112
• 12 years agoHelpfull: Yes(6) No(4)
• please give the options!!!else it is not worth solving..
• 12 years agoHelpfull: Yes(5) No(1)
• the given answer is 48.........
• 12 years agoHelpfull: Yes(4) No(4)
• erik=x
  roy=x+4
  lewis=2x+8
  x+6=2x+4
  Answer is 112.
• 12 years agoHelpfull: Yes(3) No(4)
• ans = 112
• 12 years agoHelpfull: Yes(3) No(2)
• here it is said that roy's age amoutns to half the age of lewis....
  then mr raj, how are u adding 2 yrs to the age of roy to get lewis' age????
  
  let age of erik be x yrs,
  then age of rahul is x+4 yrs
  x+4+2=2*(x+2)-------------(1)
  =>x=2
  let age of lewis be y,
  y=2*(x+4)---------(2)
  y=12
  roy's present age is 6yrs and of lewis is 12 yrs
  two yrs hence age of roy=8yrs
  " " " " " lewis=12+2=14 yrs
  hence the product of their ages is 8*14=112 yrs....
• 12 years agoHelpfull: Yes(3) No(1)
• L,R,E be ages of Lewis,Roy,Eric...
  R=E+4 ---(1)
  and also given R=((E+4)/2)+L ---(2)
  after 2 years R+2=2E ----(3)
  
  from (1) and (3) => E+4+2=2E =>E=6
  substitute E in (1)=> R=10
  substitute L,R in (2)=> 10=((6+4)/2)+L
  =>L=5
  
  so multiplication of L and R after two years=(10+2)*(5+2)=20*10=200..
• 12 years agoHelpfull: Yes(1) No(18)
• ans 18
  let roy age=r
  eric age=e
  and,lewis age=l
  then,r=e+4-----(1)
  r=e+4/2+l-------(2)
  now,after 2 years
  r+2=2(e+2)-----(3)
  from(1)and(3)
  e=2
  so,r=6,
  and l=3
  therefore in 2years r*y=(6+2)(3+2)=40
• 12 years agoHelpfull: Yes(1) No(3)
• Sorry half of that amount older than Lewis.
• 12 years agoHelpfull: Yes(0) No(3)
• ans=18
  roy age=r, erik=e, lewis=y
  according to qus..
  r=e+4....(1)
  r=e+4/2+y ...(2)
  in two years
  r+2=2(e+2)
  r=2e+2...(3)
  from (1)
  2e+2=e+4
  e=2
  from (3)
  r=6
  from (2)
  6=6/2+y
  y=3
  y*r=3*6
  =18
• 12 years agoHelpfull: Yes(0) No(12)