Q. A group of 6 members to be made from 8 boys and 6 girls. How many ways of forming group provided that there will be exactly 3 boys?

• 6C3 * 8C3 = 20*56 = 1120 groups
• 12 years agoHelpfull: Yes(63) No(8)
• 3 boys out of 8 boys & 3 girls out of 6 girls bcz total 6 member of a group where exactly 3 boys.
  8C3*6C3= 8!/(5!3!) * 6!/(3!3!)= 56*20=1120(ans)
  
• 12 years agoHelpfull: Yes(19) No(2)
• @rachana
  ur telling about probability but u need to notice is the given problem is from permutations&combinations. :)
  
• 12 years agoHelpfull: Yes(10) No(1)
• 1st of probability answers are always less than 1.Hence answer 1120 is wrong.
  let A be the ways of forming group.
  Therefore, n(A)=6C3*8C3/14C6=10/13.
• 12 years agoHelpfull: Yes(7) No(25)
• As it is given that exactly 3 boys are there in the group, it means exactly 3 girls are in the group because group is of 6 members.
  
  so, 8c3 * 6c3 =56*20=1120
• 12 years agoHelpfull: Yes(6) No(0)
• 1120
  8c3*6c3
• 10 years agoHelpfull: Yes(2) No(0)
• 8c3*6c3=56+20=76
• 12 years agoHelpfull: Yes(0) No(12)
• in the question there is nothing about girls so in a group there can be 0,1,2,3,4,5or all 6 girls
  so the ans is 8C3(6C0+6C1+6C2+6C3+6C4+6C5+6C6)=3528 :)
• 11 years agoHelpfull: Yes(0) No(4)
• ans:56/231
  14c8=231
  8c3=56
• 10 years agoHelpfull: Yes(0) No(1)