Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age? a.2 b.5/2 c.3/2 d.1

• Let Ronit’s present age be X years. Then, father’s present age =
  (X + 3X) years = 4X years.
  
  (4X + 8) =5/2 (X + 8)
  8X + 16 = 5X + 40
  3X = 24
  X = 8
  
  Hence, required ratio = (4X + 16)/(X + 16)= 48/24= 2
  
• 11 years agoHelpfull: Yes(29) No(10)
• correct ans is 11/5 though it is nt in option ...
  as father = x than son = x/3
  and other equation is x+8 = 5/2(x/3+8)
  so now we can find x as a 72 ..
  so son age will b 24
  after 16 years father 88 and son 40 the ratio will b 11/5
• 11 years agoHelpfull: Yes(20) No(12)
• From first condition equation is F=3s..
  From second condition F+2=(5/2)(S+8)
  solving we get s=24 and f=72... After 8 years age will s=32 and f=80
  therefore ratio= 5/2..
  Answer (B)
• 11 years agoHelpfull: Yes(17) No(19)
• Let son's age be x
  Father's age = 3x
  After 8 years
  3x + 8 = 2.5*(x + 8)
  x = 24
  3x = 72
  
  After16 years
  son = 24 + 16 = 40
  father = 72 + 156 = 48
  48/20 = 11 / 5
• 11 years agoHelpfull: Yes(16) No(21)
• Let x be the Son's age
  then, x+3x will be the father's age as per the condition.
  after 8 yrs,
  x+3x+8=2.5(x+8)
  therefore, x=8; // son's present age
  
  to compute dad's present age, x+3x=8+24=32 is dad's present age
  after 8 yrs,
  dad : 40 son : 16 40/16=>2.5(as per d sum)
  after further 8 yrs,
  dad : 48 son : 22
  ie, 48/22 => 2.18....
  so "2" will be the ans...
• 11 years agoHelpfull: Yes(9) No(8)
• Suppose Ronit's age be x
  fathers age be 3x+x that is equal to 4x.
  Now,
  after 8 years 4x+8= 5/2(x+8)
  solving above equation we get x=8
  
  After further 8 years 4x+16/x+16
  so putting x=8 we get 48/24 =2.
  
  So option A) 2 is the right answer
• 11 years agoHelpfull: Yes(4) No(2)
• @trusha-how F+2..in the prob it is given that after 8 years..so it should be F+8=5/2(S+8).. Isn't?clarify asap
• 11 years agoHelpfull: Yes(3) No(1)
• given:
  consider father's age as f and son's age as x
  f=3x
  after 8 years
  f+8=(5/2)(x+8)
  by solving the above we get..
  x=24
  y=72
  =>after 16 years
  x=40
  y=88
  y=(11/5)(40)
  
• 11 years agoHelpfull: Yes(2) No(10)
• kindly see..11/5 is not in option..
• 11 years agoHelpfull: Yes(2) No(2)
• F=3R.,
  Aftr 8 yrs.,.,
  
  F+8=5/2(R+8)
  2F+16=5R+16
  2(3R)+16=5R+40
  R=24 ROHIT
  
  aft further 8
  Rohit == 24+8=32
  Father == 24*3+8=80
  80/32====5/2
• 11 years agoHelpfull: Yes(2) No(2)
• ans is 2 lets ronit age is x then father's age is 4x.
  after 8 years 4x=8=5/2(x+8)
  on solving x=8
  as it is asked After further 8 years so ronits age is x+8+8=2
  and father's age is 4x+8+8=48 hence ans is 2
• 11 years agoHelpfull: Yes(2) No(0)
• 5/2 is the correct ans....
  
• 11 years agoHelpfull: Yes(1) No(6)
• dear ashima, thangamari & raj you all follow correct approach but by ur solution the ans is 5/2 please read the ques again and you definately catch ur mistake if not then ask me i wil tell you
• 11 years agoHelpfull: Yes(1) No(1)
• let son's age y and father's age=x.
  so x=3y
  x-3y=0
  aftr that 8 yrs later,x+8=5/2(y+8)
  calculating them we get x=72 and y=24 aftr 8 yrs x=80 and y=32
  so the father 5/2 times older than his son.option (b)
  
• 11 years agoHelpfull: Yes(1) No(3)
• ohh..sorry sorry...it will be 16 yrs later.so father 72+16=88 and son 24+16=40.so 11/5..
• 11 years agoHelpfull: Yes(0) No(2)
• ans father is 11/5 times to his son after 16 years..
• 11 years agoHelpfull: Yes(0) No(2)
• In general by observing the question for 8 years the ratio is decreasing to 1/2 so after another 8 years it will decrease to 1/1 so the answer is possible to be 2 but by solving in normal method the answer is 5/2.
• 7 years agoHelpfull: Yes(0) No(0)