Accenture
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Numerical Ability
Number System
Q. What is the 56743rd term in the series 1234567891011121314…….?
Option
a) 1
b) 3
c) 7
d) 5
Is there any shoetcut trick?
Read Solution (Total 3)
-
- 1 to 9=9 no.s 1 digit each no.
9 to 99=90no.s 2 digit each,total digit=90*2=180 terms
99 to 999=900 no.s 3 digit each,total digit=900*3=2700
999 to 9999=9000 no.s 4 digit each,total digit=9000*4=36,000
now till 999,we have=9+180+2700=2889 digits
till 9999 we hv=2889+36000=38889 digits
56743-38889=17854
after 9999 each no. has 5 digit
so 17584/5=3570 with remainder 4.
3570th no after 9999 =9999+3570=13569
next term=13570...4th digit=7 ..so ans=7 - 12 years agoHelpfull: Yes(49) No(10)
- Yea!! There is a short cut trick to solve this kind of questions. We need to consider the digital sum of the term. and that is the answer. digital sum of 56743=5+6+7+4+3=25=2+5=7. So, ans is 7. Simple right.!
- 8 years agoHelpfull: Yes(13) No(17)
- untill 9999 we have=2889+36000=38889 digits
56743-38889=17854
after 9999 each number have 5 digit
so 17584/5=3570 with remainder 4.
3570th no after 9999 =9999+3570=13569
next term=13570 ans=7 - 10 years agoHelpfull: Yes(0) No(0)
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