TCS
Company
Numerical Ability
Permutation and Combination
There are six multiple choice questions in the examination. How many sequences of anwers are possible, if the first two question have 3 choices each, the next two have 4 choice each and last two have 5 choices each?
Read Solution (Total 8)
-
- 3c1*3c1*4c1*4c1*5c1*5c1=3600
for any one of first three option of Q.1 we have three options in Q.2 4 option in Q.3.....this goes on... - 12 years agoHelpfull: Yes(43) No(2)
- ans) 3^2*4^2*5^2=3600
- 12 years agoHelpfull: Yes(5) No(0)
- yar abijit pls explain in full detail
- 12 years agoHelpfull: Yes(4) No(1)
- (3!*2)(4!*2)(5!*2)=138240
- 12 years agoHelpfull: Yes(3) No(16)
- @ ritu,
Is this the Question from TCS new pattern? please give me the information yar - 12 years agoHelpfull: Yes(1) No(0)
- 3600
3c1*................... - 9 years agoHelpfull: Yes(0) No(0)
- 3c1*3c1*4c1*4c1*5c1*5c1
=3*3*4*4*5*5
=9*16*25
=3600 - 9 years agoHelpfull: Yes(0) No(0)
- 3^2*4^2*5^2=9*16*25=3600
- 8 years agoHelpfull: Yes(0) No(0)
TCS Other Question