(1) From 52 cards 3 cards drawn randomly prob of getting 1 spade , 1 red queen and 1 black king??

• 13C1*2C1*2C1/52C3 = ANS
• 12 years agoHelpfull: Yes(27) No(8)
• Ans can be evaluated as 2 separate conditions
  1st
  He selects 1 of 12 spades(king removed)
  He selects a red queen i.e 1 of 2
  He selects a black king again 1 of 2
  so total probability= (12C1*2C1*2C1)/52C3
  2nd
  He selects the king of spade only one way
  He selects red queen 1 of 2
  He selects the remaining black king one way
  so total probability=(1*2C1*1)/52C3
  Adding both the totals will give u the ans ie 0.00266
• 12 years agoHelpfull: Yes(12) No(0)
• probability for spade is 13/52
  red queen is 2/51
  black king is 2/50
  total probability is 13*2*2/52*51*50
  = 1/2550
  but total combination would be 6
  total will be (1/2550) *6 =.00235
• 12 years agoHelpfull: Yes(8) No(3)
• 13C1*2C1*1C1/52C3
  1 black king involve in the spade series,so just one has left
• 12 years agoHelpfull: Yes(4) No(1)
• ans is=0.00235
  total there are 52 cards so,and we have have to select 3 cards so
  n(s)=as ncr = 52 c 3=22100,......(1)
  n(e)now e1=1 spade out of 13c1 and
  e2=1 red queen so 2c1 and
  e3=1 black king 2c1=,so 13*2*2=52 now,
  nor our equation n(e)/n(s)=
  52/22100 so,ans will be=0.00235.
• 12 years agoHelpfull: Yes(2) No(4)
• All are assuming that black king as 2...
  but it is not so here..
  in this question when we withdraw spade...then along with spade 1 black king will come out.....so in last only 1 black king is left out....
  so...
  required probablity=(13*2*1)/(52*51*50)=1/1275
• 9 years agoHelpfull: Yes(2) No(2)
• 1/425 ans.
• 12 years agoHelpfull: Yes(1) No(2)
• probability for getting spade is 13/52
  for red queen will be 2/51
  black king will be 1/50
  total will be 13*2*2*/52*51*50=1/2550
• 12 years agoHelpfull: Yes(1) No(3)
• can u explain it
• 12 years agoHelpfull: Yes(0) No(2)
• answers is : 1/2250
• 9 years agoHelpfull: Yes(0) No(0)