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two cyclist begin training on oval racecourse at same timethe professional cyclist complete each lap in 4 sec noves take 6 mintue how many mintue after start will both cyclist pass at exactly same spot where they begin to cycle(a)10(b)8(C)14(D)12
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- professional time to complete 1 lap = 4 sec
noves time to complete 1 lap = 6 minutes = 360 sec
now,
360/4 = 90 times professional complete its lap, where noves completes its lap 1 time
so, they meet again at starting point after 6 min,12 min,18 min - 12 years agoHelpfull: Yes(11) No(2)
- ans is d.
simply LCM of 4 and 6. - 12 years agoHelpfull: Yes(9) No(6)
- in this Q if we take time as 4 sec and 360 sec then their LCM will be 360sec or
"6 minute" but if we take 4/60 min and 6/1 min then after calculating LCM of numerator and HCF of denominator it gives "12 minute". Why is it happening?? please somebody explain me !! - 12 years agoHelpfull: Yes(3) No(2)
- DOLA chutiye....
6/1 aur 4/60 ka lcm 12 ayega.
coz 4/60 = 2/30 .....fraction ko proper fraction me convert kro phle...lolZ - 12 years agoHelpfull: Yes(2) No(5)
- ans:12 At 12th min professional cyclist passed 3 lap &noves passed 2nd lap so both are meet at starting point
- 12 years agoHelpfull: Yes(1) No(2)
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