WHAT IS REMAINDER WHEN
6^17+17^6 DIVIDED BY 7 ? (a)1(b)6(c)0(d)3

• Answer: 0
  
  6^17 = 6^4 * 6^4 * 6^4 * 6^4 * 6
  17^6 = 17^2 * 17^2 * 17^2
  
  (6^4)/7 gives remainder 1
  6/7 gives remainder 6
  so 1*1*1*1*6 = 6 . this is the remainder part of 6^17.
  like wise (17^2)/7 gives remainder 2.
  so 2*2*2 = 8 . this is the remainder part of 17^6.
  6^17 + 17^6 = 6 +8 = 14 . 14/7 gives remainder 0.
• 11 years agoHelpfull: Yes(12) No(2)
• ans is 0
  because 6^18mod7=1
  hence 6^17mod7=6
  by remainder theorem
  and
  17^6mod7=1
  hence(6+1)mod7=0
• 11 years agoHelpfull: Yes(6) No(5)
• Use calculator for this type of Questions,
  If the answer in calculator will not give any fraction value, then o would be the reminder
• 11 years agoHelpfull: Yes(2) No(7)
• @rishi singh
  can u explain it more clearly plz
• 11 years agoHelpfull: Yes(0) No(3)
• plz explain it more clearly
  
• 11 years agoHelpfull: Yes(0) No(0)
• according to my solution ans is 2.
  and if we directly compute the result and divide it by 7 we will get ans in fraction so remainder can never be 0.
  please someone check it out and give the right solution.
• 11 years agoHelpfull: Yes(0) No(8)