Raj tossed 3 dices and there results are noted down then what is the probability that raj gets 10?
a) 1/72 b) 1/9 c) 25/216 d)1/8

• possible event.......(1,3,6)(1,4,5)(1,5,4)(1,6,3)(2,2,6)(2,3,5)(2,4,4)(2,5,3)(2,6,2)(3,1,6)(3,2,5)(3,3,4)(3,4,3)(3,5,2)(3,6,1)(4,1,5)(4,2,4)(4,3,3)(4,4,2)(4,5,1)(5,1,4)(5,2,3)(5,3,2)(5,4,1)(6,1,3)(6,2,2)(6,3,1)
  total 27 possible event
  so probability = 27/216 i.e 1/8
  answer-------d(1/8)
• 12 years agoHelpfull: Yes(65) No(4)
• Remember when three dices are rolled or a die is rolled three times,number of ways of getting sum 'n' is
  =(n-1)C2,n=3 to 8
  =25 when n=9,12
  =27 when n=10,11
  =(20-n)C2 when n=13 to 18,
  Hence the answer for n=10 is 27/(6*6*6)=1/8
• 12 years agoHelpfull: Yes(29) No(10)
• in this according to situtaion there are so many pairs posible (1,3,6)(1,4,5)(1,5,4)(1,6,3)(2,2,6)(2,3,5)(2,4,4)(2,5,3)(2,6,2)(3,1,6)(3,2,5)(3,3,4)(3,4,3)(3,5,2)(3,6,1)(4,1,5)(4,2,4)(4,3,3)(4,4,2)(4,5,1)(5,1,4)(5,2,3)(5,3,2)(5,4,1)(6,1,3)(6,2,2)(6,3,1)
  6*6*6=216
  total pairs =216
  condition pairs=27
  so now 27/216=1/8 will be definitely answer
  
• 12 years agoHelpfull: Yes(18) No(1)
• n(E)= posible pairs=(1,3,6)(1,4,5)(1,5,4)(1,6,3)(2,2,6)(2,3,5)(2,4,4)(2,5,3)(2,6,2)(3,1,6)(3,2,5)(3,3,4)(3,4,3)(3,5,2)(3,6,1)(4,1,5)(4,2,4)(4,3,3)(4,4,2)(4,5,1)(5,1,4)(5,2,3)(5,3,2)(5,4,1)(6,1,3)(6,2,2)(6,3,1)
  n(E)=27
  n(S)=6*6*6=216
  Probability=n(E)/n(S)=27/216=1/8
• 12 years agoHelpfull: Yes(12) No(2)
• Always remember when 3 dice are rolled the number of ways of getting n ( where n is the sum of faces on dice)
  = (n−1)C2 where n = 3 to 8
  = 25 where n = 9, 12
  = 27 where n = 10, 11
  = (20−n)C2 where n = 13 to 18,
  Hence answer is (27/216)=1/8
  
• 12 years agoHelpfull: Yes(9) No(10)
• the event comes in (1,3,6)(1,4,5)(1,5,4)(1,6,3)(2,2,6)(2,3,5)(2,4,4)(2,5,3)(2,6,2)(3,1,6)(3,2,5)(3,3,4)(3,4,3)(3,5,2)(3,6,1)(4,1,5)(4,2,4)(4,3,3)(4,4,2)(4,5,1)(5,1,4)(5,2,3)(5,3,2)(5,4,1)(6,1,3)(6,2,2)(6,3,1)...i.e 27 possible event and event 6*6*6=216
  then possible event is 27/216=1/8....so a
  ans (d)
• 12 years agoHelpfull: Yes(6) No(4)
• case for getting 10 are (6,3,1) we arrange this case in 6 ways similarly
  , (6,2,2) in 3 ways
  (5,4,3) in 6 ways
  (5,4,1) in 6 ways
  (4,4,2) in 3 ways
  (3,3,4) in 3 ways
  so total no of ways for getting 10 is 27;
  required probability(10)=27/216;
• 8 years agoHelpfull: Yes(6) No(0)
• how do get the ans 27, in a simple easy way,ie in less time? any shortcuts?
• 10 years agoHelpfull: Yes(5) No(1)
• it will be 81/216.options r wrong.
• 12 years agoHelpfull: Yes(2) No(56)