Sum of 3-digit number is subtracted from number. the resulting number is divisible by

a) 6
b) 9
c) both 6 and 9
d) all 3,6,9

• b) 9
  let no. of form xyz then
  
  (100x + 10y +z) - (x+y+z) = 99x + 9y = 9*(11x+y)
  
  always divisible by 9 .
• 9 years agoHelpfull: Yes(31) No(3)
• first take the any value ,for example 123
  then add the 3 digits ,the result is 6 then
  subtract =>123-6=117,
  the 117 always divisible 9
  
• 9 years agoHelpfull: Yes(7) No(3)