TCS
Company
Numerical Ability
Age Problem
MOTHER +DAUGHTER+INFANT AGE IS 74. MOTHER AGE IS 46 MORE THEN DAUGHTER AND INFANT.
AND INFANT AGE IS 0.4 OF DAUGHTER. FIND DAUGHTERS AGE.
Read Solution (Total 8)
-
- M+D+I = 74 ..,.,.Equ..1
I=0.4D
M=D+0.4D+46
M=1.4D+46
put in equ 1
1.4D+46+D+0.4D=74 as I=0.4D
2.8D=74-46
D=28/2.8
D=10.,.,., - 12 years agoHelpfull: Yes(70) No(1)
- 2D+.8D+46=74
D=10 - 12 years agoHelpfull: Yes(18) No(3)
- according to ques:
m+d+i=74----(1)
m=46+(d+i)----(2)
i=0.4d----(3)
to find:
d=?
solution:
putting the value of eqn.(3) into eqn.(2)
m=46+(d+0.4d)----(4)
putting value of (4) and (3)into (1)
46+(d+0.4d)+d+0.4d=74
46+2.8d=74
2.8d=74-46=28
=>d=28/2.8=10
hence, daughter's age=10 - 12 years agoHelpfull: Yes(16) No(0)
- M+D+I=74
M=D+I+46 & I=0.4D
SO,2D+2I+46=74
OR,2D+0.8D+46=74
on solving,we get D=10....ans - 12 years agoHelpfull: Yes(6) No(0)
- m+d+I=74
d+i+46=m then 2d+2i=28 so 2*0.4i+2i=28
i=10 so d=0.4*10=4 - 12 years agoHelpfull: Yes(3) No(12)
- answr:4 yrs
- 12 years agoHelpfull: Yes(0) No(23)
- @viresh why u wrote 0.8D?? instead 0.4d??
- 12 years agoHelpfull: Yes(0) No(9)
- Answer is 10
- 9 years agoHelpfull: Yes(0) No(0)
TCS Other Question