Q. If the product of 3 consecutive integers is 210, then the sum of two smaller integer is:

Option
A) 5
B) 11
C) 12
D) 13
E) 18

• answer is 11
  5*6*7=210
  so 5+6=11
  by option we can do this type of question
• 12 years agoHelpfull: Yes(13) No(0)
• option (b) 11 is correct answer
  The three consecutive integers are:5,6,7
  5*6*7=210
  so the sum of two smaller integers is:5+6=11
• 12 years agoHelpfull: Yes(3) No(1)
• Ans is 11. SOLN: 5*6*7=210 then 5+6=11.
• 12 years agoHelpfull: Yes(1) No(0)
• 5*6*7=210
  5+6=11
• 12 years agoHelpfull: Yes(0) No(0)
• prime factor of 210 is 2,3 ,5,7 we have to select 3 no out these factor combination will be {(6,5,7),(10,3,7),(14,5,3),(2,15,7),(2,5,21),(2,3,35)}
  now see the answer it says sum of two smaller digit hence ,B will be the answer
  
• 11 years agoHelpfull: Yes(0) No(0)
• let 1st integer =y
  so,2nd=y+1
  3rd=y+2
  y*(y+1)*(y+2)=210
  y^3+3y^2+2y=210
  solving y=5
  no=5,6,7
  ans.>>>>>11
• 10 years agoHelpfull: Yes(0) No(0)