A Grocer bought 24 kg coffee beans at price X per kg. After a while one third of stock got spoiled so he sold the rest for $200 per kg and made a total profit of twice the cost. What must be the price of X?
A. $33 1/3 B. 66 2/3 C.44 4/9 D.50 1/3

• ans: C. 44 4/9
  
  cost price= 24*X $,
  spoiled= 24*1/3=8 kg, now total amount= (24-8)=16 kg
  selling price= 16*200$ =3200$
  profit= (3200-24*X)
  profit=2* cost , (3200-24*X)= 2*24*X, x=44 4/9
  
• 12 years agoHelpfull: Yes(48) No(5)
• c.p=24X
  Profit= 2c.p= 48X
  spoiled stock= (1/8)24=8kg
  s.p= 24-8 =16,16 x 200 $
  
  
  so prfoit= s.p -c.p
  48X = (16 x 200)- 24 X
  24 X= 32000/48 = 44 4/9
• 12 years agoHelpfull: Yes(17) No(4)
• 
  C.P. = 24x
  spoiled = 24*1/3 ==> 8kg
  remain,. 16kg he sold at 200/kg
  S.P. = 16*200 ==> 3200
  and earn profit twice the C.P.
  So, CP == 1600
  24x=1600
  x=1600/24
  x=66 2/3
  
  -------------
  tally
  x=66.666
  CP==24x
  = 24*66.6666
  = 1600 which is 1/2 of profit
• 12 years agoHelpfull: Yes(6) No(5)
• Total Cost price = 24 * x
  As 1/3rd of the beans spoiled, remaining beans are 1/3 (24) = 8kgs
  so the remainig stock is 24-8=16
  Selling price = 200 *16 = 3200
  Profit = Selling price - Cost price = 3200 - 24 X
  Given Profit = 2 Cost price
  3200 - 24 X = 2 (24 X)
  Solving X = 44.44
• 8 years agoHelpfull: Yes(1) No(0)
• total c.p=24X; (1/3)*24=8;
  so,16*200=72X; we have given profit=twice of total c.p
  X=44.44;
• 8 years agoHelpfull: Yes(0) No(0)