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Find k if the length of the tangent segment from (8, − 3) to the circle x2 + y2 − 2x + ky −23 = 0 is root10 units
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length of tangent = sqrt(8^2 + (-3)^2 - 2*8 + k(-3) -23)
sqrt(10) = sqrt (64+9 -16 -3k -23)
10 = 34- 3k
3k = 34 - 10
3k = 24
k= 8- 9 years agoHelpfull: Yes(0) No(0)
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