n! has 13 zeros than wat is the higest and lowest value of n??

• Here we have to consider only the 5,10,15,20.... these terms..
  so form (5,10,15,20,30,35,40,45,55 ) we got 1 no of zero from each.
  Now from 25(5*5) and 50(5*5*2) we got 2 no of zeroes form each.
  so upto 55 factorial we get (9+4)= 13 zeroes.
  so 55! is the smallest value and 59! is the largest value.
• 11 years agoHelpfull: Yes(51) No(11)
• @ Aditya ,
  
  pls check.
  
  65! will have 13 +2= 15 zeros.
  55! ,56!,.....59! will have 13 zeros.
  
  lowest value of n=55
  highest value of n =59
• 11 years agoHelpfull: Yes(12) No(12)
• 10! has 2 zeros.. these zeros hav cam frm 10*5*even no.
  so this means 20! will hav 4 zeros
  now 25=5*5 ohk.. so 30! has 2 times 5 and 1 time 10
  so these two 5 will multiply wd any 2 even no. n giv 2 zeros
  so in all 30! will hav 7 zeros
  nw 40! hav 9 zeros.
  50=5*5*2
  again we hav two 5
  so 50! has 12 zeros
  and till 55! we hav 13 zeros
  0n 60! we will hav 14 zeros
  so we ended at 59!.
• 11 years agoHelpfull: Yes(10) No(3)
• can anyone explain me more clearly
• 11 years agoHelpfull: Yes(9) No(1)
• Ans:- n=65 Because n!=65! has 13 zeros...65/5=13
  if we want to check in 200!
  how many zeros are there then we will divide it by 5 let see
  200/5=40; we will take again 40
  40/5=8 ; then
  8/5=1 now we will add all the ans 40+8+1=49 zeros possible in 200!
• 11 years agoHelpfull: Yes(4) No(23)
• olz expain clearly
• 11 years agoHelpfull: Yes(4) No(1)
• To find the number of zeros of factorial number we use this formula
  [n/5]+[n/5^2]+[n/5^3]+-.... so on where [] represents integral part of number..For this problem
  [n/5]+[n/5^2]+...........=13
  we should get 11+2=13 which exactly fits..To get 11+2 value of n :lowest-55 and highest --59
• 9 years agoHelpfull: Yes(2) No(0)
• 55! is the lowest value ans 59! is the max valu.
  go through the arun sharma book, chapter number system.
  
• 8 years agoHelpfull: Yes(0) No(1)
• 55! is lowest and 59! is highest.
  
• 8 years agoHelpfull: Yes(0) No(1)