A,B and C together can complete a work in 8 days.All the 3 started the work together but C quit after 2 days.If the remaining work is now completed by A and B in 9 days, then how many days will C alone will take to complete the total work??

• A + B + C Day's Work = 2/8= 1/4.
  Remaining work = 3/4.
  3/4 work is completed by A+B in 9 days.
  So, work rate of A+B is 9*4/3= 12 days.
  
  A+B+C = 1/8
  1/12+1/C = 1/8.
  1/C = 1/8-1/12
  Solving it C would complete the work in 24 days
• 8 years agoHelpfull: Yes(12) No(1)
• a+b+c=8 days , 1 days = 1/8
  c =2 days , 1 day = 1/2
  then, remaining work of a+b= 1/8-1/2= 3/8
  so , 9 days work = 9* 8/3=24 days
• 9 years agoHelpfull: Yes(11) No(3)
• (A+B+C) work in 1 day = 1/8 (B+C) work in 1 day = 1/12
  
  1/8-1/12 = 24 days
• 9 years agoHelpfull: Yes(9) No(4)
• Let, Work done in 8days BY A+B+C=X
  work done in 1 day BY A+B+C=X/8
  work done in 2 day BY A+B+C=2X/8=X/4
  Remaining work=X-X/4=3X/4.
  work done in 9 day BY A+B=3X/4.
  work done in 1 day BY A+B=X/12.
  X/12+C=X/8. [.'.A+B+C=X/8]
  work done in 1 day by C=X/24
  hence, C took 24 days to complete the work X.
  
  
• 8 years agoHelpfull: Yes(2) No(0)
• A+B=2C
  A+B+C=8 DAYS THEN
  2C+C=8DAYS
  THEREFORE C=24 DAYS
  
• 9 years agoHelpfull: Yes(1) No(6)
• (A+B+C) work in 2 day=1/4 of work;
  A+B completed 3/4 work in 9 days;
  A+B 2 day work=(3/4)*2*1/9
  =1/6
  c=(A+B+C) 2days work -(A+B) 2days work
  c total time to complete the work=1/8-1/6
  =1/24
  24 days
• 9 years agoHelpfull: Yes(1) No(0)
• -1/72
  1/9+c=1/8
• 8 years agoHelpfull: Yes(0) No(2)
• 24 days answer
• 8 years agoHelpfull: Yes(0) No(0)