Tim and Elan are 90km away from each other .they are starting to move towards eachother simultaneously ,tim at speed 10kmph and elact at 5kmph ,,if every hr they double the speed ,wht is distance that tim will pass until he meets elan?

• From que. we can see the speed of Tim is always double than speed of Elan. Therefore, Let the Speed of Elan= X, Then
  speed of Tim= 2X, and
  assume that both are covering different distance in time ="t"
  Given: Total distance= 90 Km
  Therefore, 2Xt+Xt= 90 km
  ( where xt=distance covered by Elan &
  2Xt=distance covered by Tim)
  Hence, Xt= 30 km,
  But xt is distance covered by elan, Hence Distance covered by Tim is 2Xt= 60 km
  ans: 60 km
• 12 years agoHelpfull: Yes(66) No(4)
• tim elan
  10 5 in 1st hour=15km
  20 10 in second hour=30km
  40 20 in 3rd hour=60km
  bt total distnce in 3rd hour= 90-(15+30)=45km
  total time= 2+45/60 hour
  total distance covered by tim= 10+20+3/4*40=60km
• 12 years agoHelpfull: Yes(24) No(4)
• ratio of speeds =2:1
  hence, tim distance=90*2/3
  =60km
• 11 years agoHelpfull: Yes(11) No(1)
• 1st,2nd,2(3/4) hours Tim covers the distance of 10km,20km,30km,total=10+20+40=60
  1st,2nd,2(3/4) hours Elan covers the distance of 5km,10km,15km,total=5+10+15=30
  2(3/4) means 2hours 45 min, generally 3rd hr Tim covers 40km but 45 min is sufficient
  so, they are taking 2 hours 45 min to meet each other,at that time Tim covers 60km. so ans is 60.
• 12 years agoHelpfull: Yes(3) No(5)