75 boys can complete a work in 24 days.how many men need to complete twice the work in 20 days

• one man can complete the work in 24*75=1800days = one time work
  to Complete the work twice it will be completed in
  let M be the no. of worker assign for this therefore the eqn becomes
  M*20=2*1800
  M=180 workers
• 12 years agoHelpfull: Yes(13) No(3)
• MORE WORK, MORE MEN (direct proportion)
  LESS DAYS,MORE MEN (indirect proportion)
  
  work 1:2
  :: men 75 :x
  days 20:24
  (1/2 )*(20/24) = (75/x)
  x=180
• 12 years agoHelpfull: Yes(7) No(0)
• (Man1*days)/work=(Man2*days)/work (75*24)/1=(x*20)/2 x=180
  
• 12 years agoHelpfull: Yes(4) No(0)
• to complete the work once (24*75 = 1800 ) man-days required.
  to complete the wrok twice (2*1800 = 3600) man-days required.
  no of days = 20 so
  no of workers = 3600/20
  = 180
• 12 years agoHelpfull: Yes(3) No(0)
• This question can simply solve by chain rule(Indirect proportion) as
  let x be the no of men require to do the twicee of given work in 20 days means to do the given work in 10 days
  
  Indirect proportion:
  75:x::10:24
  10x=75*24
  x=(75*24)/10=180 ans.
• 12 years agoHelpfull: Yes(2) No(0)
• efficiency of 1 person= 1/(24x75)
  so to cal. no. of days for same work
  1/(24x75) x D x 20 = 1
  D=90
  as we have to solve for twice work ans is 180 days...
  :)
• 12 years agoHelpfull: Yes(1) No(0)
• Answer is: 180 Days
• 11 years agoHelpfull: Yes(1) No(0)
• 75 boys can complete a work in 24 days or twice the work in 48 days: each boy 1/48*75 per day or 3 boys 1/48*25 per day
  
  how many men need to complete twice the work in 20 days (2mens work=3boys)
  
  2 men = 1/48*25 or 1 man 1/48*50 per day or 20/48*50 in 20 days
  
  20/48*50 = 1/24*5 = 1/240. Would take 240 men to complete twice the work in 20 days
• 12 years agoHelpfull: Yes(0) No(3)
• Answer is:125 Days
• 11 years agoHelpfull: Yes(0) No(1)
• total work=75*24=1800
  The work to complete=3600
  Days=20
  No of men=3600/20=180
• 11 years agoHelpfull: Yes(0) No(0)
• m*20=2*(75*24)
  m*20=3600
  m=180
  
• 11 years agoHelpfull: Yes(0) No(0)