The citizens of planet negate are 8 fingered and have thus developed their decimal system in base 8.
A certain street in negate contains 1000 (in base 8) buildings numbered 1 to 1000.
How many 3’s are used in numbering these buildings?

• rule is 3n^2,where n is the base no=3*8^2=192
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• 3*8^2 + 0*8^1 + 0*8^0=192
  their 300 8's from 1 to 1000
  
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• there are 300 3's in between 1 -1000
  (300)base 10=(192)base 8 {3*8^2 + 0*8^1 + 0*8^0=192}
  so answer is 192
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