int get(int n)
{
if n<1 get(n-1);
get(n-3);
return (0);
}

If get(6) is called through main then how many times get() function is called?

• first time it checks the condition ,since condition not satisfied it executes else part and exits the function.
  so only once it is called
  
• 10 years agoHelpfull: Yes(0) No(0)
• results in infinite loop run.. as no break condition is provided.
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• 
  infinite times
  1 ... get(6) excute else part it will call get (6-3) so
  2 ....get(3) ...... excute else part it will call get (3-3) so
  3 ... get(0)..... excute if part get(0-1)
  4 ..get(-1) so it will never terminate ,will call for -2,-3,-4.........
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• After getting in condition n
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