A shop stores x kg of rice. The first customer buys half this amount plus half a kg of rice. The second customer buys half the remaining amount plus half a kg of rice. Then the third customer also buys half the remaining amount plus half a kg of rice. Thereafter, no rice is left in the shop. Which of the following best describes the value of x?
A. 2 ≤ x ≤ 6
B. 5 ≤ x ≤ 8
C.9 ≤ x ≤12
D. 11≤ x ≤ 14

• after 1st customer, x-x/2-1/2=(x-1)/2
  after 2nd customer, (x-1)/2-(x-1)/4-1/2=(x-3)/4
  after 3rd customer, (x-3)/4-(x-3)/8-1/2=(x-7)/8=0
  x=7 Hence option B.
• 12 years agoHelpfull: Yes(11) No(1)
• A. 2 ≤ x ≤ 6 B. 5 ≤ x ≤ 8 C.9 ≤ x ≤ 12 D. 11≤ x ≤ 14
  these are the options
  
• 12 years agoHelpfull: Yes(2) No(1)
• Initial quantity of the rice = x
  The first customer buys half the total rice and another half kg.
  Rice purchased by first customer = x/2 + 1/2 = (x + 1)/2
  So, rice left after the first customer = x - (x + 1)/2 = (x - 1)/2
  Now the second customer buys half the left rice and another half kg.
  Rice purchased by second customer = (x - 1)/4 + 1/2 = (x + 1)/4
  So, rice left after the second customer = (x - 1)/2 - (x + 1)/4 = (x - 3)/4
  Now the third customer buys half the left rice and another half kg.
  Rice purchased by third customer = (x - 3)/8 + 1/2 = (x + 1)/8
  So, rice left after the second customer = (x - 3)/4 - (x + 1)/8 = (x - 7)/8
  Given that (x - 7)/8 = 0 => x = 7
  So option (b) is correct.
• 8 years agoHelpfull: Yes(2) No(0)
• b option is correct
  by hit and trial method
  by taking x=6 and 8.
  we get -ve value when we put x=6 and we get +ve value when we put x=8.
  so the value must lie between 6 and 8.
• 12 years agoHelpfull: Yes(1) No(0)