What is the largest number that will divide 90207, 232585 and 127986 without leaving a
remainder?
a) 257 b) 905 c) 351 d) 498

• HCF is the best solution. bit its time taking.
  see the numbers 90207 , 232585 , 127986.
  choose 905. but its not possible because last digit must be 0 or 5.
  choose 498. it is also not possible because last dight must be an even number.
  only 2 left now.
  its easy now to get the answer by division method :)
  ans is 257.
  
• 10 years agoHelpfull: Yes(78) No(0)
• 232585 - 127986 =104599
  127986 - 90207 = 37779
  
  since 37779 < 104599
  
  v use 37779
  1st 37779/257=147
  37779/905=41.74....
  37779/351=107.6....
  37779/498=75.8....
  
  so ans is 257
• 9 years agoHelpfull: Yes(13) No(0)
• ans. A .take the HCF of 90207,232585 & 127986
• 10 years agoHelpfull: Yes(11) No(3)
• we understand that answer is the HCF of all the numbers, but we need not to actually calculate the HCF, just a little observation will help you to get through in seconds by reducing the options.. first check the numbers, and the options, as 498 is one of the options, that means, all the numbers should be even number as 498 is also an even number, but only 127986 is even so 498 is not the option, then we check the divisibility by 3, so 232585 is not divisible by 3, that means amongst the options, one which is divisible by is not the correct one, 351 is not the answer, then for being divisible by 905, numbers should be divisible by 5 as well, but only 232585 is divisible...so 905 is also not the correct answer, so we are left with 257 as correct answer... :) :)
• 8 years agoHelpfull: Yes(10) No(0)
• subtract 2 to 1,2 to 3 then u can tak a hcf of two numbers
• 10 years agoHelpfull: Yes(9) No(4)
• A) 257
  easily u can chk by division
• 10 years agoHelpfull: Yes(3) No(5)
• as division by 905 and 498 is not possible
  so either 257 or 351
  now HCF them
  we get 257 as the answer.
• 10 years agoHelpfull: Yes(3) No(0)
• first we can find out H.C.F of the three number given,, and will check with the given calculator which option adjust correctly. therefore
  option A-257 fitts correctly,..
  
  shortest way to solve during tcs written exam. :)
• 9 years agoHelpfull: Yes(3) No(9)
• wil u plss explain it clearly
• 10 years agoHelpfull: Yes(2) No(0)
• eliminate 905 and 498.check either by divisibility rule or gcd.for e.g. 351 is divisible by 3 but 232585 is not divisible by 3....
• 9 years agoHelpfull: Yes(1) No(1)
• 351
  by process of elimination
  
• 8 years agoHelpfull: Yes(1) No(0)
• A is a correct answer
• 10 years agoHelpfull: Yes(0) No(2)
• 257 is the correct answer
  
• 10 years agoHelpfull: Yes(0) No(0)
• 257 divisible to all nunber
  
• 10 years agoHelpfull: Yes(0) No(1)
• ANS IS ; A
• 10 years agoHelpfull: Yes(0) No(0)
• pls explain clearly..
• 10 years agoHelpfull: Yes(0) No(0)
• hcf of no
  use elimination method and reject 905 and 498
• 9 years agoHelpfull: Yes(0) No(0)
• 257 is the answer
• 9 years agoHelpfull: Yes(0) No(0)
• x/6+x/4+x/6+32=x
  
  24x-14x=768
  
  768/10=76.7(app.77)
  
  77+13=90
  ans=90
• 9 years agoHelpfull: Yes(0) No(2)
• just find the gcd......its 257
• 9 years agoHelpfull: Yes(0) No(0)
• by doing HCF
  ans will be a) 257
• 9 years agoHelpfull: Yes(0) No(0)
• 257)90207(351
  771
  -----------------
  1310
  1285
  -------------------
  257
  257
  --------------------
  000
  so ans is 257
  
• 9 years agoHelpfull: Yes(0) No(0)
• Given numbers are 90207,127986 and 232585.
  
  To Get the greatest number which divides given numbers without leaving a remainder.
  
  i.e find the HCF of given numbers.
  90207=3*3*3*13*257
  127986=2*3*83*257
  232585=5*181*257
  => 257 is the largest number.
• 5 years agoHelpfull: Yes(0) No(0)