Four friends namely Rahul, Ravi, Rajesh and Rohan contested for a dairy milk chocolate. To decide which friend will get the chocolate they decided to throw two dice. Every friend was asked to choose a number and if the sum of the numbers on two dice equals that number, the concerned person will get the chocolate. Rahul's choice was7, Ravi's choice was 9, Rajesh's choice was 10 and Rohan's choice was 11. Who has the maximum probability of winning the amount.

a) Rahul b) Ravi c) Rajesh d) Rohan

• Rahul has max chance
  as there are max options for getting 7 with two dice.
  1+6
  2+5
  3+4
  4+3
  5+2
  6+1
  where as for other cases, there are relatively less options.
• 11 years agoHelpfull: Yes(45) No(2)
• Rahul has chosen 7, similarly Ravi-9,Rajesh-10,Rohan-11
  (1,1)(1,2)(1,3)(1,4)(1,5)(1,6) Sum of the digits are= 2,3,4,5,6,7
  (2,1)(2,2)(2,3)(2,4)(2,5)(2,6) Sum of the digits are= 3,4,5,6,7,8
  (3,1)(3,2)(3,3)(3,4)(3,5)(3,6)Sum of the digits are= 4,5,6,7,8,9
  (4,1)(4,2)(4,3)(4,4)(4,5)(4,6)Sum of the digits are= 5,6,7,8,9,10
  (5,1)(5,2)(5,3)(5,4)(5,5)(5,6)Sum of the digits are= 6,7,8,9,10,11
  (6,1)(6,2)(6,3)(6,4)(6,5)(6,6)Sum of the digits are= 7,8,9,10,11,12
  Among these 7 comes 6 times, 9 comes 4times, 10 comes 3times,11 comes only 2 times.
  So the maximum probability goes to Rahul
• 11 years agoHelpfull: Yes(20) No(1)
• Rahul has maximum probability
  11--->(5,6),(6,5)--->2 combinatioins
  10--->(6,4),(4,6),(5,5)----> 3 combinations
  9---->(6,3),(5,4),(4,5),(3,6)---->4 combinations
  7---->(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)----> 6 combinations
• 11 years agoHelpfull: Yes(10) No(0)
• total sample space=6*6=36
  event which is in favor of rahul's choice sum7 ={(1,6)(2,5)(3,4)(6,1)(5,2)(4,3)}
  p(rahul wins)=1/6
  event which is in favor of ravi's choice sum9 ={(4,5)(3,6)(5,4)(6,3}
  p(ravi wins)=1/18
  BY SAME METHOD
  P(RAJHESH WINS)=1/12
  P(ROHAN WINS)=1/18
  
  HENCE
• 11 years agoHelpfull: Yes(3) No(1)
• for Rahul (1,6),(2,5),(3,4),(4,3),(5,2,)(6,1) p=6/36=1/6
  for ravi (3,6),(4,5),(5,4),(6,3) p=4/36=1/9
  for rajesh(5,6),(6,5) p=2/36=1/18
  for rohan (6,6) p=1/36
  clearly Rahul has maximum......
  
• 11 years agoHelpfull: Yes(3) No(1)
• send me a latest tcs pattern urgent 3 days after i have...
  ramesh.1234565@yahoo.in
• 11 years agoHelpfull: Yes(1) No(0)
• ravi with 6 chances
  
• 11 years agoHelpfull: Yes(0) No(5)
• Go with the options....
  try one by one. Monday is correct......
• 11 years agoHelpfull: Yes(0) No(0)