10 FEB 2015 : Distance and Speed
A car starts from rest and accelerates uniform upto speed 90 km/hrs in 5 sec. Total distance covered by car in this time will be

OPTION 1) 50
2) 52.5
3) 55
4) 57.5
5) 60
6) 62.5
7) 65
8) 67.5
9) 70
10)72.5

• average speed=0+25/2=25/2
  distance=25/2*5=125/2=62.5
  
  option 6.
• 9 years agoHelpfull: Yes(0) No(0)
• Vi = 0 m/sec (Initial speed)
  Vx = 90 KM/Hrs = 25 m/sec
  T = 5 sec
  D = 1/2 (Vi + Vf) T
  D = 1/2 (0+25) 5
  D = 1/2 (125)
  D = 62.5 meters
  
  Option 6.
• 9 years agoHelpfull: Yes(0) No(0)
• 90km/hr=90000/3600=25m/sec;
  here acceleration(f) of the car is=(25-0)/5=5m/sec;
  so the distance covered by the car is=0*5+(.5*5*5*5)=62.5m;
• 9 years agoHelpfull: Yes(0) No(0)