f(n) is a function...where f(f(n))+f(n)=2n+3.
f(n)=0;find f(2012

• 2n+3
  f(0)+0=2n+3
  F(0)=2n+3
  so
  function not dependent on value inside bracket
  so 2n+3
  
• 11 years agoHelpfull: Yes(45) No(3)
• In this question f(0)=1;
  f(f(n))+f(n)=2n+3;
  let n=0,1,2,3,4,....
  so n=0
  f(f(0))+f(0)=2*0+3
  f(1)+1=3
  f(1)=2
  n=1
  f(f(1))+f(1)=2*1+3
  f(2)+2=5
  f(2)=3
  same as n=2012
  f(2012)=2013
  
• 11 years agoHelpfull: Yes(30) No(8)
• hai guys yesterday I came up with TCS written before the date of written test pls get ur application to be TPO approved otherwise ur paper wil not be evaluated eventhough u have gone up with written.....n take calci to the exam
• 11 years agoHelpfull: Yes(26) No(4)
• f(0)=2n+3
  f(2012)=(2*2012)+3
  =4027
• 11 years agoHelpfull: Yes(10) No(35)
• ye TPO kya hai...? please tell me any one
• 11 years agoHelpfull: Yes(8) No(7)
• Answer : f(2012)= 2013
  Becoz, f(0)=1 ,f(1)=2, f(2)=3......and so f(n)=n+1
  
  
  
• 11 years agoHelpfull: Yes(4) No(12)
• f(n)=0
  so any value in n gives zero
  so answer is zero
• 11 years agoHelpfull: Yes(4) No(0)
• f(n)=0 hence from eqnwe get f(0)=2n+3
  from defination of function we get function not dependent on value....
  so answer should be 2n+3 here..
• 11 years agoHelpfull: Yes(3) No(2)
• i think the question is posted wrongly.
  f(f(n))+f(n)=2n+3
  f(0)=1
  then find f(2012)?
  then.
  f(f(0))+f(0)=3
  f(1)+1=3
  f(1)=2
  
  f(f(1))+f(1)=5
  f(2)=3
  similarly ..........f(3)=4......
  f(2012) = 2013
  
  
• 10 years agoHelpfull: Yes(3) No(0)
• @krati: In preplacement talk v were told tht vll get 35 qsns and how r u so sure that new pattern contains 30 qsns?
• 11 years agoHelpfull: Yes(2) No(1)
• question is wronge
  
• 11 years agoHelpfull: Yes(2) No(4)
• first sub...
  we get...n= -3/2
  so if n=-3/2
  then f(n)=0
  ..............hmmmm i have no clue....
• 11 years agoHelpfull: Yes(1) No(4)
• Put n = 0
  Then f(f(0))+f(0) = 2(0) + 3 ⇒ f(1) + 1 = 3 ⇒ f(1) = 2
  Put n = 1
  f(f(1)) + f(1) = 2(1) + 3 ⇒ f(2) + 2 = 5 ⇒ f(2) = 3
  Put n = 2
  f(f(2)) + f(2) = 2(2) + 3 ⇒ f(3) + 3 = 7 ⇒ f(3) = 4
  ......
  f(2012) = 2013
• 8 years agoHelpfull: Yes(1) No(0)
• krati: did u appear for tcs apti??
• 11 years agoHelpfull: Yes(0) No(5)
• @raj:no..i dint..
• 11 years agoHelpfull: Yes(0) No(3)
• @raj: when did i tell nytng abt ques pattern?
• 11 years agoHelpfull: Yes(0) No(1)
• @krati:sorry i guess i might have seen sum other post and thot it was u !! when do u have aptitude ??
• 11 years agoHelpfull: Yes(0) No(2)