Miscellaneous Company Exam
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. In a garden, trees are planted in rows. In each row there are as many trees as the number of rows in the garden. If each tree bears as many fruits as the number of trees in each row and if the total number of fruits from the trees in that garden is n, then :
1) n is a perfect square 2) n is an odd number
3) n is an even number 4) n is a perfect cube.
Read Solution (Total 4)
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- n is a perfect cube..
say for example, there are 4 rows in d garden, then there will b 4 trees in each row and each tree wud bear 4 fruits..Then total no of fruits in d garden wud b (4*4)*4= 64...which is a cube of 4....hence the ans is D. - 12 years agoHelpfull: Yes(11) No(0)
- n is perfect cube.
x no of row
1 row -> x trees
x row -> ?
no of trees=x^2
1 tree -> x fruits
x^2 trees -> ?
no of total fruits= x^3 - 12 years agoHelpfull: Yes(3) No(0)
- option a...by
n=no.of fruits in one tree*total tre es=m*m=n
both are same. so it is perfect sqaure - 12 years agoHelpfull: Yes(0) No(5)
- let the no of row br x
then,the no of tree is also x
therefore, total no of trees in garden = x*x
now,
no. of fruits in a single tree is also x.(according to given condition)
therefore total no of fruits be x*x*x
given that total no of fruits = n
hence
n= x*x*x
which is perfect cube
hence answer 4) is correct - 10 years agoHelpfull: Yes(0) No(0)
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