sum of the digits of a 3 digit number is substracted from the number. the resultung number is divisible by

a.6
b. 9
c. Both 6 and 9
d. All 3,6 and 9

• let digit is xyz
  so it can be written 100*x+10*y+z;
  and we are removing x+y+z so 100*x+10*y+z-( x+y+z )=99*x+9*y
  so it will be divisibal by 9 always
  
• 7 years agoHelpfull: Yes(4) No(0)
• suppose, let the three digit number =999
  sum of the digits=9+9+9=27
  then substract from the 3digit num =999-27=972
  it is divisible by both 6 and 9
  
• 8 years agoHelpfull: Yes(0) No(5)