A man loses 1/3rd of his money, then wins Rs. 10 loses 1/3rd of what he has and wins Rs. 20 and finds that he has exactly what be had at the beginning. What was the amount he originally bad ?

1] 25 2] 36 3] 10 4] 48

• let x be that amount
  so accordind to question , eqn will be like:
  (((x-x/3)+10)-(((x-x/3)+10)/3))+20=x
  => ((2x/3+10)-((2x/3+10)/3))+20=x
  =>3x-4x/3=80
  =>x=48
• 12 years agoHelpfull: Yes(7) No(0)
• ans is rs 48
• 12 years agoHelpfull: Yes(5) No(0)
• ANS is 4)48
  consider x as his initial money
  1st case--->(x-x/3+10)=(2x+30)/3
  2nd case--->((2x+30)/3)-((2x+30)/9)+20
  x=48
• 12 years agoHelpfull: Yes(3) No(1)
• let x be that amount
  so accordind to question , eqn will be like:
  case 1. x-x/3+10=(2x+30)/3
  case 2 (2x+30)/3-(2x+30)/(3*3)+20
  =>(4x+240)/9
  
  according to last condition
  =>(4x+240)/9=x
  =>4x+240=9x
  =>5x=240
  x=48
  
• 10 years agoHelpfull: Yes(0) No(0)