x and y are 2 numbers which when divided by 6 leave a remainder of 4 and 5 respectively. what will be the remainder when y+x is divided by 6?

a.6
b.9
c.1
d.none

• x/6=4
  28/6=4
  x=28
  when 28 is divided by 4 it leaves remainder 4
  similarly
  y/6=5
  35/6=5
  y=35
  (28+35)/6=63/6=3
  so option D
• 9 years agoHelpfull: Yes(41) No(5)
• ALWAYES REMANDER WILL BE 3
  BECAUSE 4+5=9
  WHICH IS 3 GREATER THEN 6
  SO ANS IS D
• 9 years agoHelpfull: Yes(25) No(2)
• x/6=4
  24/6=4
  so,x=24
  y/6=5
  30/6=5
  so,y=30
  
  (24+30)/6=54/6=9
  
  ans=9 option (b)
  
  
• 9 years agoHelpfull: Yes(10) No(52)
• remainder is 3
  let x=64 y=65
  x+y= 129 when 129 divided by 6 remainder is 3
• 9 years agoHelpfull: Yes(7) No(6)
• according to the condition:
  Suppose X=10
  y=11
  divide by 10 and 11 it leave reminder 4 and 5
  now Y+X=21
  divide 21/6=3
• 9 years agoHelpfull: Yes(6) No(1)
• say two numbers as x y
  i can take like this x=28 28%6=4
  y=35 35%6=5
  x+y=63 63%6=3 so ans is 3
  
• 9 years agoHelpfull: Yes(4) No(2)
• they asked about remainder
  so 6)10(1
  6
  rem=4
• 9 years agoHelpfull: Yes(3) No(12)
• x=6+4=10;
  y=6+5=11;
  y+x=21; is divided by 6 then remainder is 3
  so ans none
• 9 years agoHelpfull: Yes(3) No(0)
• Simple frmula,
  R=(r1+r2)-divisor
  R=(4+5)-6=3
• 8 years agoHelpfull: Yes(3) No(0)
• here in the first case 5 n 4 are xtra..if we add x n y this xtra i.e 5 n 4 will also add up..then if x+ y divides by 6 the remainder will be {(5+4)-6}=3
• 9 years agoHelpfull: Yes(2) No(2)
• let x=10/6=rem 4
  y=11/6=rem 5
  x+y=>10+11=21/6
  ans-3
• 9 years agoHelpfull: Yes(1) No(3)
• in each and every case the remainder will be 1 whether (10+11)/6 the remainder will be 1 or (64+65)/6 the remainder will be 1
• 9 years agoHelpfull: Yes(1) No(8)
• lets take 10 n 11 so 10/6,11/6 = 4,5 as remainders.. now add 11 n 10 =21/6 gives 3..so deres no option with 3 den none is ans!!
• 9 years agoHelpfull: Yes(1) No(1)
• Remainder will be 3....but 3 is not mentioned in option so answer is none i.e D
• 9 years agoHelpfull: Yes(1) No(1)
• answer B
  x/6=4 ==10/6
  y/6=5 == 11/6
  (y+x)/6 = (11+10)/6
  = 3
  = 3+6= 9 , 15, 21 ....... if answer is different
• 8 years agoHelpfull: Yes(1) No(1)
• x=10, y=11
  x+y=21
  21/6=3
  asn d
• 6 years agoHelpfull: Yes(1) No(0)
• x=16 and y=17
  x/6 i.e. 16/6= remainder 4
  y/6 i.e. 17/6= remainder 5
  y+x/6 i.e. 17+16/6= remainder 3
  so ans is d bcz 3 is not present in option.
• 5 years agoHelpfull: Yes(1) No(0)
• option d
  4+5=9/6=3(remainder)
  so option d
• 4 years agoHelpfull: Yes(1) No(0)
• 0 answere
  
• 9 years agoHelpfull: Yes(0) No(5)
• (4+5)/6=9/6=3 s0, remainder is 3
• 7 years agoHelpfull: Yes(0) No(1)
• x/6=4
  then x=24;
  
  Now,
  y/6=5
  then y=30;
  
  ATP,
  (y+x)/6=(24+30)/6=54/6=9;
  
  So Ans is 9;
• 7 years agoHelpfull: Yes(0) No(2)
• x=24
  y=30
  y+x=54
  54/6 = 9
  y+x/6 = 9
• 5 years agoHelpfull: Yes(0) No(1)
• x=6*4=24 and y=6*5=30
  The value of x and y is 24 and 30 respectively
  x+y=54
  54/6=9
• 5 years agoHelpfull: Yes(0) No(0)
• 10,16,22,......are the numbers which leaves remainder 4
  11,17,23......are the numbers which leaves remainder 5
  10+11=21/6=gives 3 as remainder
  16+17=33/6=gives 3 as remainder
• 4 years agoHelpfull: Yes(0) No(0)
• The ans will be none. As the ans us 3 is not present in the options. Take any 2 numbers multiple of 6 and add 4,5 respectively, then divide the sum of the results by 6 , you always find the result as 3
• 4 years agoHelpfull: Yes(0) No(0)
• X=6a+4
  y=6b+5,where a and b are arbitrary integers
  y+x= 6a+6b+5+4
  =6(a+b)+9
  ={6(a+b)+6}+3
  =6(a+b+1)+3
  Remainder=3
  Therefore answer: (d) none
• 4 years agoHelpfull: Yes(0) No(0)
• According to the question, when x is divided by 6 then a remainder of 4 is obtained.
  
  So, x = 6a + 4
  
  Similarly y = 6b + 5 [ where a and b are two positive integers. ]
  
  Squaring the both side of equations:
  
  X² = 36a² + 48a + 16 ………………….(i)
  
  Y² = 36b² + 60b + 25……………………..(2)
  
  
  
  Now add equation (i) and equation (ii)
  
  X² + Y² = 36a² + 36b² + 48a + 60b + 41
  
  X² + Y² = 6 ( 6a² + 6b² + 8a + 10b + 6) + 5
  
  So
  
  X² + Y² = 6m + 5 [ where m = (6a² + 6b² + 8a + 10b + 6) ]
  
  Now by euclids division lemma X²+Y² when divided by 6 leaves a remainder 5.
  
  So the answer is 5.
• 2 years agoHelpfull: Yes(0) No(0)