Ravi has a bag full of 10 nestle and 5 cadbury chocolates out of these, he draws two chocolates. what is the probability that he would get atleast one nestle chocolates?

a.19/21
b.3/7
c.2/21
d.1/3

• a. 19/21
  
  Selecting atleast one nestle chocolate=(1 nestle & 1 cadbury) or 2 nestle
  So probability of selecting 2 out of 15=[(10C1*5C1) +10C2 ]/ 15C2 =[ (10*5) + 45]/ 105 =35/105=19/21
• 9 years agoHelpfull: Yes(13) No(1)
• Option a
  Both nestle = 10c2= 45
  1 nestle + 1 Cadbury =10c1 * 5c1 =50
  
  45+50=95
  
  Total event 15c2= 105
  
  Probability =95/105= 19/21
• 9 years agoHelpfull: Yes(3) No(0)
• 15c2=105
  (10c1*5c1)+10c2=95
  =95/105=19/21
• 9 years agoHelpfull: Yes(1) No(0)