What is the remainder when 6^17+17^6 is divided by 7 ?
a) 1
b) 6
c) 0
d) 3

• Ans : 0
  6^17 mod 7 =(7-1)^17 mod 7=(-1)^17 mod 7 = -1
  17^6 mod 7 =(7*2+3)^6 mod 7= (3)^6 mod 7 = 729 mod 7 = 1
  Thus, the remainder when 6^17+17^6 is divided by 7 is
  (-1)+1 = 0
• 12 years agoHelpfull: Yes(44) No(4)
• 6^17^/7=(-1)^(16+1)=-1 i.e 6 & 17^6/7=(3^2)^3/7=2^3/7=8/7=1
  s0 reminder is 6+1=7 hence 7/7 reminder is 0. answer is c)0
• 12 years agoHelpfull: Yes(8) No(4)
• 6^17/7 can be written as (7-1)^17mod7=-1 mod 7=-1
  
  17^6/7 can be written as (7*2+3)^6mod7=3^67mod7=729mod7=1
  
  the remainder is -1+1=0
  
• 10 years agoHelpfull: Yes(3) No(0)
• 0
  6^17 mod 7 =(7-1)^17 mod 7=(-1)^17 mod 7 = -1
  17^6 mod 7 =(7*2+3)^6 mod 7= (3)^6 mod 7 = 729 mod 7 = 1
  Thus, the remainder when 6^17+17^6 is divided by 7 is
  (-1)+1 = 0
• 11 years agoHelpfull: Yes(1) No(0)
• d remainder will be 3
• 9 years agoHelpfull: Yes(0) No(1)