In an exam, Ajith, Sachu, Karna, Saheep and Ramesh scored an average of 39 marks. Saheep scored 7 marks more than Ramesh. Ramesh scored 9 fewer than Ajith. Sachu scored as many as Saheep and Ramesh scored.Sachu and Karna scored 110 marks them. If Ajith scores 32 marks then how many marks did Karna score?

• 57
  
  If marks of Ajith=u, Sachu=v, Karna=w, Saheep=x and Ramesh=z , then
  z+7=x ---(i)
  u- 9=z ---(ii)
  x+ z=v ---(iii)
  v+w=110 ---(iv)
  Also given, u=32, So from (ii), z=23 & from (i), x=30, from (iii), v=53, from (iv),w=57
• 9 years agoHelpfull: Yes(7) No(2)
• ajith=32
  ramesh=32-9=23
  saheep=30 so karan 57
• 9 years agoHelpfull: Yes(4) No(0)
• Average score of them = 39 marks.
  Then the total marks of them = 39 x 5 = 195 marks.
  
  Ajith have scored 32 marks.
  Ramesh scored 9 fewer than Ajith. Ramesh's mark = 32 - 9 = 23
  
  Saheep scored 7 more than Ramesh = 23 + 7 = 30
  
  Sachu scored as many as Saheep and Ramesh.
  i.e., 23 + 30 = 53
  
  Sachu and Karna have scored 110 marks.We know that Sachu had scored 53 marks.
  Sachu + Karna = 110
  53 + Karna = 110
  Karna = 110 - 53 = 57
  Hence the score of karna is 57 marks
• 7 years agoHelpfull: Yes(2) No(0)
• a=x //ajith marks if x=32
  r=x-9 //ramesh marks
  sh=r+7=x-2 //saheep marks
  sc=sh+r=2x-11 //sachu marks
  sc+k=110 //sachu and karan marks =110
  then sc=53 then k=110-k
  =>k=110-53
  =>57
  
• 9 years agoHelpfull: Yes(0) No(0)
• Let marks of Ajith = a ; Sachu = sc ; Karna = k ; Saheep = sh and Ramesh = r then
  sh – r = 7 - - - - (i)
  a – r = 9 - - - - (ii)
  sc = sh + r - - - - (iii)
  sc + k = 110 - - - - (iv)
  Also given a = 32
  So from (ii) r = 23 and from (i) sh = 30 , from (iii) sc = 53, from (iv) k = 57.
• 5 Months agoHelpfull: Yes(0) No(0)